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26th February 2016, 11:06 | #1 | Link |
I'm Siri
Join Date: Oct 2012
Location: void
Posts: 2,633
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(further) lossless compression with pi?
so π (the ratio of a circle's circumference to its diameter) is (very likely to be) normal (mathematically "normal", not "normal" normal) like, a common sense..
which equals to any combo of 0-9 will eventually appear somewhere within the infinite digits of π.. well, after typical lossless compression, the statistic redundancy of the compressed data will be like, none and makes further (lossless) compression almost impossible but I guess π could help here, since any random base 10 data will appear somewhere within the digits of π like eventually, an extra compression could be done by the following steps: 1. convert the binary to many base 10 data blocks 2. search the data block in the digits of π, if any match found, mark the matching digit position a1 and the length of data block a2 3. if the size of a1+a2 >= the data block itself, abort the rest steps and start the next data block matching, if not, replace the whole data block with a1 and a2 4. repeat step 1-3 till all data blocks are matched what do you think? |
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